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std::alignment_of

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C++
 
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alignment_of(C++11)
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Заголовочный файл <type_traits>
template< class T >
struct alignment_of;
 (начиная с C++11)
Обеспечивает постоянный член value равно требование выравнивания типа T, как бы получить alignof выражение. Если T является типом массива, возвращается требования к выравниванию типа элемента.
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Provides the member constant value equal to the alignment requirement of the type T, as if obtained by an alignof expression. If T is an array type, returns the alignment requirements of the element type.
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Содержание

Унаследован от std::integral_constant

Member constants

value
[static]
 alignof(typename std::remove_all_extents<T>::type)
(public static константа-член)

Member functions

operator std::size_t
преобразует объект в std::size_t, возвращает value
Original:
converts the object to std::size_t, returns value
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(public функция-член)

Member types

Type
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Type
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 Definition
value_type std::size_t
type std::integral_constant<std::size_t, value>

[править] Возможная реализация

template< class T >
struct alignment_of : std::integral_constant<
                          std::size_t,
                          alignof(typename std::remove_all_extents<T>::type)
                       > {};

[править] Пример

#include <iostream>
#include <type_traits>
 
class A {};
 
int main()
{
    std::cout << std::alignment_of<A>::value << '\n';
    std::cout << std::alignment_of<int>::value << '\n';
    std::cout << std::alignment_of<double>::value << '\n';
}

Вывод: 

1
4
8

[править] См. также

alignof operator queries alignment requirements of a type (начиная с C++11) [edit]
(C++11)
определяет тип подходит для использования в качестве неинициализированные для хранения типов заданного размера
Original:
defines the type suitable for use as uninitialized storage for types of given size
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(шаблон класса) [edit]
(C++11)
определяет тип подходит для использования в качестве неинициализированные для хранения всех данных типов
Original:
defines the type suitable for use as uninitialized storage for all given types
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(шаблон класса) [edit]
(C++11)
POD типа с требованием выравнивания так велика, как любой другой тип скаляра
Original:
POD type with alignment requirement as great as any other scalar type
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(определение типа) [edit]
Источник — «http://ru.cppreference.com/mwiki/index.php?title=cpp/types/alignment_of&oldid=31397»