std::remainder
Материал из cppreference.com
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| Заголовочный файл <cmath>
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| float remainder( float x, float y ); |
(1) | (начиная с C++11) |
| double remainder( double x, double y ); |
(2) | (начиная с C++11) |
| long double remainder( long double x, long double y ); |
(3) | (начиная с C++11) |
| Promoted remainder( Arithmetic x, Arithmetic y ); |
(4) | (начиная с C++11) |
Вычисляет остаток с плавающей x/y операции деления точка. В отличие от
4) fmod, возвращаемый тип будет отрицательным, если fmod(x, y)>y/2.Original:
Computes the remainder of the floating point division operation x/y. In difference to
fmod, the return type will be negative if fmod(x, y)>y/2.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Если какой-либо из аргументов имеет целый тип, он приведен к double. Если любой другой аргумент long double, то возвращаемый тип long double, иначе это double
Original:
If any argument has integral type, it is cast to double. If any other argument is long double, then the return type is long double, otherwise it is double
The text has been machine-translated via Google Translate.
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[править] Параметры
| x, y | - | с плавающей точкой
Original: floating point values The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[править] Возвращаемое значение
остаток от деления аргумента
Original:
remainder of dividing arguments
The text has been machine-translated via Google Translate.
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[править] См. также
| Остальная часть операции с плавающей точкой разделения Original: remainder of the floating point division operation The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (функция) | |
| (C++11) |
частное и остаток от деления Original: the quotient and remainder of integer division The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (функция) |