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std::vector::erase

Материал из cppreference.com

 
 
 
std::vector
Член функций
Original:
Member functions
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vector::vector
vector::~vector
vector::operator=
vector::assign
vector::get_allocator
Элемент доступа
Original:
Element access
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vector::at
vector::operator[]
vector::front
vector::back
vector::data(C++11)
Итераторы
Original:
Iterators
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vector::begin
vector::cbegin

(C++11)
vector::end
vector::cend

(C++11)
vector::rbegin
vector::crbegin

(C++11)
vector::rend
vector::crend

(C++11)
Потенциала
Original:
Capacity
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vector::empty
vector::size
vector::max_size
vector::reserve
vector::capacity
vector::shrink_to_fit(C++11)
Модификаторы
Original:
Modifiers
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vector::clear
vector::insert
vector::emplace(C++11)
vector::erase
vector::push_back
vector::emplace_back(C++11)
vector::pop_back
vector::resize
vector::swap
 
iterator erase( iterator pos );
iterator erase( const_iterator pos );
(1) (до C++11)
(начиная с C++11)
iterator erase( iterator first, iterator last );
iterator erase( const_iterator first, const_iterator last );
(2) (до C++11)
(начиная с C++11)
Удаляет указанные элементы из контейнера.
Original:
Removes specified elements from the container.
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1)
Удаляет элемент pos.
Original:
Removes the element at pos.
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2)
Удаляет элементы в диапазоне [first; last).
Original:
Removes the elements in the range [first; last).
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Iterators and references to the erased elements and to the elements between them and the end of the container are invalidated.

Содержание

[править] Параметры

pos -
итератор на элемент для удаления
Original:
iterator to the element to remove
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first, last -
диапазон элементов для удаления
Original:
range of elements to remove
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[править] Возвращаемое значение

Итератор, следующих за последним удаленным элементом.
Original:
iterator following the last removed element.
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[править] Пример

#include <vector>
#include <iostream>
 
 
int main( )
{
    std::vector<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
 
    c.erase(c.begin());
 
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
 
    c.erase(c.begin()+2, c.begin()+5);
 
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
}

Вывод:

0 1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9
1 2 6 7 8 9

[править] Сложность

1) linear in the distance between position and last.

2) linear in distance between position and the end of the container.

[править] См. также

удаляет содержимое
(public функция-член) [edit]